Question:

Audio frequency comms splitter impedance matching

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I have a splitter transformer with a single multi-tap primary (175 77 98 turns), and two independent secondary coils of 175 turns each.

The transmitter is 600 Ω and connected to the primary, and a 600 Ω receiver is connected to each of the secondaries. (ie two separate 600 Ω receivers)

How many turns on the transformer primary are required to match the loads on both the secondaries?

Do I calculate each reflected secondary load independently, and then calculate the result as two parallel impedances in the primary?

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  1. I believe so.

    You want 600 reflected in the primary, so that's 1200//1200 for the reflected Z.

    To get 1200 reflected in the primary for each 600 ohm load, you would calculate

    Zr = N^2.Zs    (N is turns ratio primary/secondary)

    rearranging and plugging in values to find N:

    N = sqrt(1200/600) or 1.414 (ie root 2).

    Each secondary winding is 175turns, so the primary should be 175*1.414, or 247 turns, so use the 175 turn and the 77 turn taps in the primary for 252 turns, which will put you close to 600 ohms total reflected load.

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