Question:

Autally my doubt is ,how to increase the battery discharge or decrease the discharge while design the UPS?

by  |  earlier

0 LIKES UnLike

let us consider we are going to design an UPS for a system.client wants the battery back up time is 4 hrs for 500 KW. the next day the same client wants to upgrade the back up time to 7 hrs. In this case we know that our battery discharge should be less when compared to 4 hours back up.here doubt is how to calculate the ampere hour of battery for 4 hrs ,and 7 hrs for the same load.(500 KW).

 Tags:

   Report

4 ANSWERS


  1. 4h x 500kW = 2000 kWh

    7h x 500kW = 3500 kWh

    kiloAmpere-hours = kWh divided by volts.

    Assuming 120V,

    2000 kWh / 120V = 16.6 kAh

    3500 kWh / 120V = 29.2 kAh

    I would suggest a diesel generator the size of a mini-van, complete with auto-transfer switch as your UPS.


  2. Volts is missing from your problem so we'll assume 120volts.

    p = i times e,  so i equals 500000/120=4166 amps per hour.

    So your battery, which is rated in amp hours will be 4 X 4166 amp hours or 7 X 4166 amp hours. of course if your battery is some other voltage, say 12 VDC, then multiply the above  times a factor of 10.

  3. huh?

    you are designing this? You are asking some basic questions.

    500 kW is a very large UPS. Very! enough to run 100 homes. The largest UPS that APC makes is 9.6 kW and that costs $10000, and it has a backup time of 30 minutes. You would need 50 of these!

    If you want the operating time on battery to go from 4 hr to 7hr, you need a bigger battery. No way around that.

    500 kW is increased due to efficiency losses in the inverter, so figure 600 kW. For 7 hours that is 4200 kw-hrs.

    A large lead acid battery has a capacity of 100 amp hours, which translates to 1000 watt-hrs or 1 kW-hr.

    You will need *** 4200 *** large lead acid batteries to hold for 7 hours, and 2400 batteries for 4 hours.  Enough for a large submarine.

    I think some of your numbers are wrong. First rule: get the numbers correct!

  4. Double it(ok  multiply it by 7/4ths which is a little less than double).Twice the time at the same load.

Question Stats

Latest activity: earlier.
This question has 4 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.