A(x plus c) equals b (x minus c)?

Question

solve for x

All i can do is distribute before i get lost.

Answer 1

I think this is the answer.

(space) bx-bc

x=__ _________

(space) Ac

_   __________

(space) A

Which is said "X equals bx minus bc over ac all over A"

I think your step after distributing is to divide both sides by the same thing to balance the equation.  so your first step

divide ax+ac by ac leaving ax, and divide bx-bc leaving bx-bc over ac

and then divide ax by a leaving x,

and divide bc-bx over ac by a leaving bx-bc over ac all over a.

Answer 2

You have the first step right - distribute

a(x+c)=b(x-c)

ax+ac=bx-bc

Now, get all the terms with x in them over to the left side by subtracting bx from both sides

ax+ac-bx=-bc

Get all the terms without x in them over to the right by subtracting ac

ax-bx=-bc-ac

Factor an x out of each of the terms on the left

x(a-b)=-bc-ac

Now, divide both terms by (a-b)

x=(-bc-ac)/(a-b)

To make it look prettier, you might want to factor the top, too:

x=-c*(b+a)/(a-b)

_/

Answer 3

The farthest you can go, seeing as you have no actual solved numbers to work with, is to simply distribute the problems.

1. A(x+c) = B(x-c)

2. A(x+c)

    B(x-c)

3. AB (x)

Since you cannot solve this problem any more due to lack of data, this is the simplified answer.

Hope I helped! :]