Question:

Back emf question?

by  |  earlier

0 LIKES UnLike

What is the back emf of a 120 V motor that draws 12.0 A at its normal speed and 40.0 A when first starting?

 Tags:

   Report
Answer The Question I've Same Question Too

1 ANSWERS

Sort By: Date  |  Rating

  1. The resistance is:

    R = Ɛ / I = 120 V / 40.0 A = 3.00 Ω

    The back emf is:

    Ɛ (back) = - (IR - Ɛ) = - ((12.0 A x 3.00 Ω) - 120 V) = 84.0 V

You're reading: Back emf question?

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Register Now
Unanswered Questions