Balancing Redox Equations

Question

Balance the following equation in acidic solution using the lowest possible integers and give the coefficient of water.

I2(s) S2O32-(aq) ® S4O62-(aq) I-(aq)

Please show me how to do this!

Answer 1

 It splits into the following half reactions:

reduction:

I2 + 2e- --> 2I-

and oxidation:

2S2O3-2 --> S4O6-2 + 2e-

adding them together you get and cancelling out electrons you get:

2S2O3-2 + I2 --> S4O6-2 + 2I-

Answer 2

 It splits into the following half reactions:

reduction:

I2 + 2e- --> 2I-

and oxidation:

2S2O3-2 --> S4O6-2 + 2e-

adding them together you get and cancelling out electrons you get:

2S2O3-2 + I2 --> S4O6-2 + 2I-

Answer 3

 You're wrong, this is a redox equation, and Sulfur changes from +2 to +3, and in order to balance you need to know whether its reacting within an acid or within a base.