Basic math problem, really stuck though..?

Question

3x*x - 2x + 3 = 4x + 3

3x*x - 2x + 3 - 4x - 3 = 0

3x*x - 6x = 0

3x*x (x - 2) = 0 <-- what happened to the 6x?

Answer 1

That last line should be

3x(x-2) = 0

If you factor in the 3x, you get 3x*x - 6x back out.

Make sense?

Answer 2

it was factored out...greatest commmon factor was 3x

at that point, theres no need to write it anymore because it was cancelled out

Answer 3

the last step you typed is wrong, it&#039;s actually:

3x(x-2) = 0

The 6x disappeared because you factored the expression. If you multiply that last step you get 3x^2 - 6x = 0.

Answer 4

Your last equation is wrong: 3x*x - 6x =0 (dunno how to say this in english so i&#039;m just gonna do it) therefore 3x ( x-2) =0. Good day!

Answer 5

the 6x got put into the brackets.

6 divided by 3 is 2 and then you have to put the x in as well therefore it becomes (x - 2)

hope that helps.

Answer 6

Using the distributive property, you know that -2 times 3 equals -6. Add an x and that&#039;s how the 6x disappeared!

Answer 7

You were going fine until the last step...

3x*x - 6x = 0

Is the same as 3x(x-2) = 0 Your answer would have given you:

3x*x*x - 6x*x when you multiplied it back out

Answer 8

3x*x - 6x = 0 turns into 3x * (x - 2) = 0

This is because 3x * x = 3x*x and 3x * -2 = -6x

Answer 9

My friend, the last step is wrong. lets go back to

3x^2-6x=0

I know a lot of people want and know how to factor, but a sure bet is completing the square, but you need to remember that

(a^2-2ab+b^2) = (a-b)^2

now looking at 3x^2-6x=0 which is also x^2-2x=0 Do you agree?

so set x^2 =a^2 and 2x=2ab and solve for b

b=1 = 2x/2a and from x^2=a^2 you know x=a, so b = 2a/2a   ok?

now write

x^2-2x+1^2=0+1^2

but x^2-2x+1=(x-1)^2=1

so x-1=Sqrt(1)= + - 1

so one x=1-1=0

the other x=1+1=2

solution: x(0,2)  

Answer 10

3x^2 - 2x + 3 = 4x + 3

3x^2 - 6x = 0

Factorizing,

3x(x-2)=0

3x=0, x=0

x-2=0, x=2