C. Calculate the pH of a solution made by combining 40.0 milliliters of 0.14 molar HOCl and 10.0 milliliters ?

Question

of .56 molar NaOH.

HOCl ↔ OCl- + H+

Ka, for the reaction represented above is 3.2 x 10-8.

Answer 1

Moles HClO = 0.14 M x 0.0400 L = 0.0056

Moles ClO- = 0.56 M x 0.010 L =0.0056

total volume = 0.0500 L

concentration HClO = concentration ClO- = 0.0056 / 0.0500 = 0.112

pKa = 7.49

pH = 7.49 + log 0.112 / 0.112 = 7.49