C# opendialog problem? ?

Question

i want to get a file name using opendialog form and then copy that file to a new location. how should i write?

thanks.

Answer 1

Well, the filename of a opendialog is OpenFileDialog1.FileName; (in case you're using 'OpenFileDialog1'). Now you only need the Move method of the System.IO namespace. The code should look like this:

File.Copy( OpenFileDialog1.FileName, "newPath" );