C6H12O6 --> 2C2H5OH + 2CO2 Starting with 500.4 g of glucose, what is the maximum amount of ethanol in grams?

Question

... and in liters that can be obtained by this process? (Density of ethanol = 0.789 g/ml)

Answer 1

Moles glucose = 500.4 g / 180.16g/mol =2.78

the ratio between glucose and ethanol is 1 : 2

moles ethanol = 2.78 x 2 =5.56

Mass ethanol = 5.56 mol x 46.068 g/mol =  256.1 g

V = 256.1 / 0.789 = 324.6 mL => 0.325 L