CHEMISTRY MATH PROBLEMS???

Question

find the number of moles of Ag needed to form .8520 mol Ag2O

a formula would be nice

thanks

Answer 1

smoorthey is right

there are two molecules of Ag in Ag2O

so there are 2*0.8520=1.0740 moles Ag

or  4 moles Ag + 1 mole O2= 2 mole Ag2O   or  4 Ag + 1 O2 ---> 2 Ag20

So the ratio would be 2 moles to 1 mole Ag2O

so 2/1*.8520=1.0740 moles Ag

Answer 2

The answer is 1.7040 mol Ag...

When doing stiochiometry problems its best to ask yourself what exactly is the question is talking about. To make Ag2O you need one atom of O and 2 atoms of Ag for each product molecule Ag2O. A mole is 6.02 * 10^23 atoms; a mole is just a unit, just like a meter has 100 centimeters, a mole has 6.02 * 10^23 atoms. Because you want 0.8520 mol of Ag2O and each Ag2O molecule has 2 Ag atoms, you need 2 *  0.8520 mol worth of Ag.

Answer 3

Find the molar mass of Ag2O using the periodic table, use that to find out how many grams of Ag2O make up .8520 mol.  Then since I assume that Ag2O comes from the rxn of Ag and O2 by thermodynamic principles, etc, this becomes a simple problem of stoichiometry.