Calc 2 problem need some help?

Question

A circular swimming pool has a diameter of 12 m, the sides are 3 m high, and the depth of the water is 1.5 m. How much work (in Joules) is required to pump all of the water over the side? (The acceleration due to gravity is 9.8 m/s^2 and the density of water is 1000 kg/m^3.)

Answer 1

The volume of water is:

pi (12 / 2)^2 * 1.5 m^3.

Its mass is:

m = pi (12 / 2)^2 * 1.5 * 10^3 kg.

It is lifted an average distance of:

h = (1.5 + 3) / 2

= 2.25 m.

The work done is:

W = mgh

where g = 9.8 m/s^2.

W = pi (12 / 2)^2 * 1.5 * 10^3 * 9.8 * 2.25

= 3.74 * 10^6 J.

Answer 2

You must have asked this question in Physics section.

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