Calculate Kc for the following reaction

Question

Given: A(l) 3B(aq) ↔ C(aq) 2D(s)

Kc = 2.45x10^-58

Calculate Kc for the following reaction

2C(aq) 4D(s) ↔ 2A(l) 6B(aq)

A. 1.57x10^-29

B. 4.08x10^57

C. 6.00x10^-116

D. 1.67x10^115

E. 6.39x10^28

the answer is D but im confused how he go it, please help

Answer 1

For the given reaction:

Kc=[D]²*[C]/[A] [B]³

For the second reaction:

K1= [A]² *[B]^6/[C]*[D]² = ( [A][B]³/[C]*[D]²)² = (1/Kc)² // by comparison.

-> K1 = 1,666*10^115 , so answer D) is correct.