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Calculate partial pressure in dry air of NO given total pressure and temp?

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Use the data in Table 5.4 to calculate the partial pressure of NO in dry air assuming that the total pressure is 1.0 atm. Assuming a temperature of 0°C, calculate the number of molecules of NO per cubic centimeter. Component: NO Mole Fraction: 0.0000005

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  1. Calculate partial pressure in dry air of NO given total pressure and temp?

    I don't know what table 5.4 is,...as long as this 1 atm is dry air:

    the partial pressure is the same as the mole fraction

    mole fraction of 0.0000005 , .... or 5e-7 moles NO per mole mix,  has a partial pressure of

    5e-7 atm  out of the 1 atm

    your answer is 5e-7 atm NO

    ==================================

    if table 5.4 is a vapor pressure table, then we need to decrease the total pressure of 1 atm by the water vapor pressure at 0 celsius, which is 0.006 atm = 0.994 atm

    then the partial pressure of NO is (5e-7)(0.994) = 4.97e-7

    but why bother, considering significant digits ... it is still rounds off to 5e-7atm

    but  i still wish I knew what table 5.4 was all about

    ======================================...

    assuming that the total pressure is 1.0 atm. Assuming a temperature of 0°C, calculate the number of molecules of NO per cubic centimeter.

    ==========

    calculate the moles in one cubic centimetre, (1e-3 litres):

    PV=nRT

    (5e-7atm)(1e-3litres) = n (0.08206L-atm/mol-K)(273K)

    n= 2.23e-11 moles of NO are in that 1 cc (aka 1e-3Litres)

    ==========

    calc the molecules in that 1cc:

    2.23e-11 mol NO @ 6.022e23 molecules / mole = 1.34e13

    your answer is 1.3 e13 molecules per cc

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