Calculate "intersect point"?

Question

1) line y=(cosγ/sinγ)z have

point x=a(1+dcosθ/cosγ),z=dsinθ/cosγ,y=0

2)cylinder y^2+x^2=r^2 for -∞<=z<=+∞

3)conditions are

r>a+d

0<γ<π/2

0=<θ=<2π

then how to calculate "intersect point" of two function-line and cylinder ?

regards/junho lee

Answer 1

&#039;mrlee&#039; you need to rephrase the problem. 1st the equation y = (cos y/ sin y ) z or z = y tan y is NOT a line in 3 space, it is a surface parallel to the x axis. Hence it meets the cylinder of 2) in a closed curve. The &#039;point&#039; given has y = 0 , thus z = 0 also { it is on the surface}.This implies either d = 0 or Θ = 0. If d = 0 then x = a while if Θ = 0 then x = a + ad.But the fact that the surface has a point on the x axis means the entire x axis lies on the surface {the graph is parallel to the x axis}.And finding the curve of intersection is more than I wish to do.