Calculate the change in potential energy of 6.2 million kg of water dropping 50 m over Niagara Falls.?

Question

Calculate the change in potential energy of 6.2 million kg of water dropping 50 m over Niagara Falls.?

Answer 1

well, you have to change the 6.2 kg into newton so basically multiply by 10 which is 62 and now multiply 62 with the 50m which should equal to 3100joules

Answer 2

PE = 1/2*mgh

so here's how to do it:

m=6.2x10^6kg

g=9.81

h=50

50x6.2x10^6x9.81=3041100000

the change in potential energy is 3.04x10^9 times 0.5

ans:1.52x10^9

hope this helps!

Answer 3

alot