Calculate the mass of 1.00 ft^3 of gold metal?

Question

Sorry, I didn't want to make it sound like I wanted you to just do the problem cause I said so. I just don't understand how to solve it. Can you guys help? If you can explain how you solved it that would be great!

Answer 1

One cubic foot of water weighs 62½ pounds and gold has a

specific gravity of 19.3, which means it is 19.3 times as dense

as water.  Thus if you multiply it out you see that one cubic

foot of gold weighs 1207 pounds.  Yes, gold is VERY heavy!

Answer 2

density = mass/volume

density of gold = 19.32g/cm^3

volume in cm^3 =1*28 316.8466  = 28 316.8466 cm^3

mass= 19.32*28 316.8466 =547081.476 grams = 547.081kg

Answer 3

Density of Gold  = 19.3 g/cm³

given volume = 1.00 ft³

we can convert the feet volume to cm³ volume:

1 ft³  = 27763.07 cm³

we just apply definition of density:

d = m/V

m = d*V = (27763.07cm³)(19.3 g/cm³) = 535827.40 g

m = 535.827 kg

If you want to reconvert this mass into pounds you get:

m = (535.827 kg)(2.205 lb / kg) = 1181.50 lb

That's all!

Good luck!

Answer 4

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