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Calculate the molar solubility of Fe(OH)2 when buffered at pH=7.0?

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  1. To answer this question you need Ksp for Fe(OH)2 which is 8.0 x 10^-16.

    Fe(OH)2(s) <==>  Fe2+(aq)  +  2OH-(aq)

    Ksp = [Fe2+][OH-]^2

    At pH = 7, [OH-] = 1 x 10^-7

    8.0 x 10^-16 = [Fe2+](1 x 10^-7)^2

    0.080 M = [Fe2+] = [Fe(OH)2]

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