Calculate the molarity of (M) of 36.5 g HCL in 1.0 L of solution?

Question

Calculate the molarity of (M) of 36.5 g HCL in 1.0 L of solution?

Answer 1

n(HCl) = 36.5/(1 + 35.5)

            = 1 M

Molarity = 1/1

             = 1mol L^(-1)

I think.............

Answer 2

Given:

mass of solute = 36.5g

volume of solution in liters = 1.0L

molar mass of HCl = 36.46g/mol

Molarity = moles of solute / volume of solution (in liters)

moles of solute = mass of solute / molar mass of solute

Therefore

Molarity = (mass of solute / molar mass of solute) / volume of solution (in liters)

Molarity = (36.5g / 36.36g/mol) / 1.0L

Molarity = 1.00mol/L = 1.0M

Answer: 1.0 M