Calculate the number of moles of a gas the occupy 7.3*10^3 Ml at STP. the value of R=0.0821 L atm mol^-1k^-1

Question

so confused :(

Answer 1

first convert the volume of gas to liters

7.3 x 10^3 mL = 7.3 L

use ideal gas Law PV=nRT

STP is Standard Temperature and Pressure

Temperature = 273.15 degrees Kelvin

Pressure is 1 atmosphere

P = 1atm

T = 273.15 degrees K

n = no. of moles

V = 7.3 L

R = 0.0821

solve for n

n = (1 atm*7.3 L)/((0.0821L*atm/(mol*K))*273.15 K) = 0.325 mol