Calculate the pH after the addition mL

Question

Calculate the pH after the addition of 55.26 mL of KOH in the titration of 50.00 mL of 0.12 M HBr with 0.15 M KOH.

Answer 1

55.26mL of KOH 0.15M (strong)

+

50.00mL of HBr 0.12M (strong)

=

105.26mL of

KOH 0.15M*55.26mL/105.26mL = 0.079M

+

HBr 0.12M*50mL/105.26mL = 0.057M

KOH + HBr ----> KBr + H2O

0.079__0.057____/_____/_

0.079-___0______/_____/_

0.057=

0.022

KOH --> K+ + OH-

0.022____/____0_

__0______/___0.022

pOH = -Log(0.022) = 1.66

pH = 14-1.66 = 12.34