Calculate the partial pressure of hydrogen gas at equilibrium.?

Question

Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3) at 200°C in a closed container. 1.16 atm of nitrogen gas is mixed with 2.17 atm of hydrogen gas. At equilibrium the total pressure is 2.17 atm. Calculate the partial pressure of hydrogen gas at equilibrium.

Answer 1

N2    &    3 H2 --> 2 NH3

(1.16-x)  (2.17 -3x) --> 2x

(1.16-x) &  (2.17 -3x) &  2x  = 2.17

-4x +2x = 2.17 -1.16 - 2.17

-2x = - 1.16

x = 0.58 atm

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H2 = 2.17 atm - 3x

H2 = 2.17 - 3(0.58)

H2 = 2.17 -1.74

your answer: H2 = 0.43 atm