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Calculate the ratio of electric to gravitational force b/w two electrons..?

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Calculate the ratio of electric to gravitational force b/w two electrons..?

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  1. Both are inverse square law, so the ratio stays the same irrespective of distance.  The electric force is F= Q1Q2/(4 pi epsilon r^2) and the gravitational force is F=GM1M2/ (r^2).  G is Newton's gravitational constant, epsilon is the electric permittivity of space, Q1,Q2,M1,M2 are the charges and masses respectively, and this works out that the electric force is about 10^39 times as strong as gravity; a very large ratio.


  2. Gravitational attraction between two electrons is:

    Fgrav = G m^2 / r^2

    Electrostatic repulsion between two electrons is:

    Felec = k q^2 / r^2

    The ratio, therefore, is kq^2 / Gm^2.

    Go look up coulomb's constant, k, newton's big G, and the mass and charge of an electron. Then grab a calculator and plugnchug.

    2 hours ago

  3. dunno

  4. mistress bekki is correct

    k = 8.99x10^9 Nm^2/C^2

    G = 6.67x10^-11 Nm^2/kg^2

    e = -1.60x10^-19 C

    m = 9.11x10^-31 kg

  5. The electric force is given by the equation Fe=(q)(q) / (4) (π) (ε0) (r^2)

    Where Fe is the electric force, either q is the charge of an electron (-1.6E-19 Coulombs), π is pi (3.14), ε0 is the permittivity of free space (8.854188E-12), r^2 is the radius squared (this will cancel out with the gravitational force)

    The gravitational force is Fg=(G) (m^2) / r^2

    Where Fg is the force of gravity, G is the gravitational constant (G=6.67E-11), m^2 is the mass squared (8.3E-61), r^2 is again the radius squared.  

    When we make a ratio of the two forces we get Fe/Fg = (q^2) (r^2) / (r^2) (4) (π) (ε0) (G) (m^2)

    The two r^2 cancel and we finally get:

    Fe/Fg = (q^2) / (4) (π) (ε0) (G) (m^2)

    This gives us a ratio of about 4.17E42.  That's a huge difference!

  6. Gravitational attraction between two electrons is:

    Fgrav = G m^2 / r^2

    Electrostatic repulsion between two electrons is:

    Felec = k q^2 / r^2

    The ratio, therefore, is kq^2 / Gm^2.

    Go look up coulomb's constant, k, newton's big G, and the mass and charge of an electron.  Then grab a calculator and plugnchug.

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