Calculate the standard entropy change for the reaction P4(g) + 5O2(G) --> P4O10(s?

Question

using the data from the following table:

Substance

P4 58.9 24.5 279.9

O2 0 0 205.0

P4O10 -2984 -2698 228.9

Answer 1

 the answer is -1076J/K 

you take the delta s values for the sum of the products times the coefficients minus the sum of the reactants times the coefficients.

so it is

228.9- (279.9+(5x205))

Answer 2

I don't have the answer but the other guy who solved it solved for enthalpy, not entropy. Don't listen to him.