Calculate the theoretical boiling point of the sodium chloride solution?

Question

Calculate the theoretical boiling point of the sodium chloride solution?

Given: MW(NaCl)=58.45 g/mol

Kb(H2O)=0.512 degress Celsius/m

Answer 1

I am going to assume that the molality 1.075 , is the moles of NaCl mixed with the solvent.  if so, then because NaCl releases twice as many moles of ions, the total molality of this solution is also twice: 2.150 molal

dTemp = K (molality)

dT =( 0.512 C / molal)2.15 molal)

dT = 1.1 C

your answer should be 101.1 Celsius,  

Answer 2

delta T = kb x i x m

you didn't give enough info

what's the molality of this solution?

but heres how to do it:

i = 2 (there's two ions. Na+ and Cl-)

m = you didn't give us, but it's ...          moles of NaCl that you have divided by the kg of water you have.

i x kbx m = your delta T

100- delta T = your final answer

100 - (i x kb x m )

100 - ( 2 x .512 x m ) = your theoretical BP

(you need to give us m)