Calculate ▲Gº for this process at 25ºC:?

Question

Consider the auto-ionization of water at 25ºC

H2O (l) ↔ H(aq) + OH(aq) Kw = 1.00 x 10^-14

2) At 40ºC, Kw = 2.92 x 10^-14. Calculate ▲Gº at 40ºC

Answer 1

ΔG = -R∙T∙ln(K)

1) At 25°C=298.15K

ΔG = - 8.314472 ∙ 298.15K ∙ ln(1.0×10⁻¹⁴) = 79.91kJ/mol

2) At 40°C=313.15K

ΔG = - 8.314472 ∙ 313.15K ∙ ln(2.92×10⁻¹⁴) = 81.14kJ/mol