Calculating proportions in reactions...?

Question

Okay, the question is:

What mass of Barium Sulphate would be produced from 10g of Barium Chloride in the following reaction:

BaCl2 + H2SO4 → BASO4 + 2HCL

I know you need to work out the number of moles first, but then i get a bit lost...

thanks

Answer 1

The question implies the BaCl2 is the limiting reagent, i.e. that is will be fully consumed in the reaction. Thus, the amount of BaSO4 will depend only on the amount of Ba at the start.

1. Calculate mol of BaCl2 from its MW and the 10 gr given.

2. Mol (BaCl2) = mol (Ba) before = mol (Ba) after = mol (BaSO4)

3. Use mol (BaSO4) & its MW to get # of grams.

Answer 2

1) Convert the mass of BaCl2 to moles by dividing 10 g by the gram formula mass of BaCl2

2) Use the mole ratio of 1 BaCl2 : 1 BaSO4 to determine the number of moles of barium sulfate produced

3) Convert moles to grams by multiplying the moles of BaSO4 by barium sulfate's gram formula mass.