Calculating the concentration of hydrogen ions from the following results???

Question

Can anybody show me how to calculate the number of H+ ions(with working) in this solution from the following results. It is neutralization reaction of acid (coke) and a base (NaOH)

We used:

1ml of Coke mixed with 20 mls of distilled water and added 0.33mls of NaOH which was 0.1 molar.

I know the calculations are something like concentration times volume or something like that. For this task we have to find the percentage of H+ ions in Coke (basically the acidity). You help would be much appreciated.

Thanks :-)

Answer 1

OH- + H+ --> H20

mols of OH- = 0.33(0.1) = 0.033 mmols

mols of H+ = mols of OH-

                  = 0.033 mmols

ummm...for the rest of the question, i am not sure what is it that you are looking for. If you say % H+ ions, do you mean the molarity of the H+ ion in the coke solution. If that is what you are looking for then you have

concentration of H+ in coke solution = 0.033 mmols/ 1mL = 0.33 M