Calculus Evaluate the Indefinite Integral!?

Question

((arcsinx)^7/sqrt(1-x^2))dx

Can anyone show me how to do this please?

Answer 1

∫(sinֿ¹(x))^7 / √(1-x²) dx

u = sinֿ¹(x)

du = 1/√(1-x²) dx

∫(sinֿ¹(x))^7 / √(1-x²) dx

= ∫u^7du

= (1/8)u^8 + c

= (1/8)(sinֿ¹(x))^8 + c

Answer 2

u = arcsin x makes it trivial