Calculus Help PLEASE!!!

Question

Use long division to evaluate the integral

Integral (x/ (x-6)) dx

Answer 1

Let s = x / (x - 6).

Then:

s = [ (x - 6) + 6 ] / (x - 6)

= 1 + [ 6 / (x - 6) ].

int[ s ] dx

= x + 6 ln(x - 6) + c.