Calculus Help Please!?

Question

Hi everyone,

How do I do this calculus problem?

Evaluate the function at the given value(s) of the independent variable. Simplify the results.

f(x) = sin x

a) f(pi)

b) f(5pi/4)

c) f(2pi/3)

Please help! Thanks!

Answer 1

just substitute the given to the equation

like f(pi)= sin(pi)

f(5pi/4)= sin(5pi/4)

f(2pi/3)= sin(2pi/3)

Answer 2

a) f(pi) = sin (pi) =0

b) f(5pi/4) =

PI=180

5PI/4=225 =180+45 = sin(45)=sin(PI/4) = 1/sqrt(2)

Since 225 lies in the third quadrant, sine is negative.

sin(5PI/4) = -1/sqrt(2)

c)sin (2PI/3)

PI=180

2PI/3=120=180-60 = sin(60) =sqrt(3)/ 2

Answer 3

Remember, there are 2 pi radians in a circle; so pi radians is 180 degrees.  The sin of 180 degrees is 0.  You can do the rest.

Answer 4

Just plug in for x in f(x)

a) x = pi

   f(pi) = sin(pi) = 0

I think you can do the rest just using a calculator...hope this helped

Answer 5

study your unit circle

a) f(pi)=0

b) f(5pi/4)= -sqrt(2)/2

c) f(2pi/3)=  sqrt(3)/2