Calculus I Help? 10 pts. best answer!!!!!!!!!!!!!?

Question

I have to find the limit as x approaches zero for this equation:

(4+x)^3-64 / x.

After I did the calculations I got that the limit was 48. Is that right?

Answer 1

Plug in different values for X, start at 1, then go to .1, .05, .01, .001, .0001.

This is a quick check and should give you a good idea what the limit should be, this looks like you have take the limit from the left and right..

Your limits are not 48.

your limit from the left hand side (-.1,-.001,-.00001,etc)is positive infinity

and from the right (.1,.01,.001,.000001, etc.) it is negative infinity

Answer 2

yes

Answer 3

(x+4)^3 - 64 / x

=(x^3 + 12x^2 + 48x + 64 - 64)/x

=x^2 + 12x + 48

so yes, the limit is 48