Can anybody find the equation of the line?

Question

I really need help with my Math homework.

Help somebody?

It says:

Find the equation of the line through the point (3, -5) which is parallel to the line with the equation 3x + 2y - 5 = 0.

Anybody help?

I don't understand.

Answer 1

-2y=-3x+5

y=-3x/-2 + 5/-2

the equation is y = 3x/2 + 5/-2

Answer 2

YOU ARE AN IDIOT!

Answer 3

first put the equation of the line into slope-intercept form(y=mx+b)...

3x+2y-5=0

3x+2y=5

2y=-3x+5

y=(-3/2)x+5/2

parallel lines have the same slope, so the equation for the second line will be

y=(-3/2)x+b now put 3 in for x and -5 in for y to solve for b

-5=(-3/2)(3)+b

-5=(-9/2)+b

b=-1/2

so the final equation would be

y=(-3/2)x-1/2

Answer 4

bollocks homework why do we need algebra in life

Answer 5

2y=- 3x +5 so all lines parallel to it have tangant of -3/2,

then Y-(-5) / X-3 = -3/2, 2Y+10=-3X+9,then the equationn you need is

Y=(-3X-1)/2

Answer 6

3x +2y -5 = 0

2y=-3x-5

y= -3/2x-5/2

parallel means same slope

y=-3/2x+b

plug in 3,5

5=-3/2(3)+b

5=-9/2+b

5+9/2=b

b=9 1/2

Answer 7

ok.

the general equation of a straight line is

y = mx +c

where y and x are points on the y and x axis, m is the gradient of the line and c is the intercept of the line and the y axis.

so first i would rearrange your equation so that it looks more like the general equation of a straight line.

if a line is parallel to another line it must have the same gradient. you can get the gradient of your line as it is the m in the general equation of a straight line.

finally using the equation of a straight line and substituting in your values of x and y for your new line and the gradient you have just found you can find c. and so write the equation of your new line.

Answer 8

First set to intercept form:

2y=-3x+5

y=-3/2x+5/2

Slope=-3/2

Point slope:

y+5=-3/2(x-3)

distribute

y+5=-3/2x+9/2

simplify:

y=-3/2x-1/2 !

Answer 9

You need to know that the general form/equation of a line is

y = mx + b

m is the slope and b is the intercepting point.

so first write your equation into that form:

you have 3x + 2y - 5 = 0

rearrange your equation so it looks liek the general form by isolating y on one side of teh equal sign , and the rest to the other side.

2y=-3x+5    -->   y = -3/2  x + 5/2

your m (or slope)  will be -3/2

Answer 10

3x+2y+p=0 as (3,-5) is on

9-10+p=0 so p= 1

and 3x+2y+1=0 is the solution

Answer 11

First of ally if it parallel to the given line, it has the same slope. The line given has the slope

y = -3/2x +5/2

-3/2

Hence, the equation of our line is

y = -3/2 x + b

Let's find b given the fact that it passes through (3,-5):

-5 = -3/2 x 3 + b

Hence b = -5 + 9/2 =  -1/2

Answer: y = -3/2x - 1/2

Answer 12

WOAH! that's confusing I'm c**p at maths - bottom set for it at school, always have been always will be...when it comes to maths I'm an idiot. I feel sorry for you having homework like this, algebra has no purpose other than to really p**s everyone off.