Can anyone help with my Algebra 2?

Question

Can anyone help me solve this problem?

1.) 3(x+4)=3x+6

Answer 1

First you multiply the 3 by both things in parenthesis.

        3x+12=3x+6

Then you put the variables on one side and the numbers on the other.

        3x+12=3x+6

       -3x       +3x

       12=6x+6

      - 6          -6

       6=6x

Then divide the variable by the number in front of it

       6=6x divided by 6 is: x=1

So x equals 1!

Hope that helped!

Good luck!

Answer 2

3(x+4)=3x+6

3*x and 3*4=12

3x+12=3x+6

    -12      -12

3x=3x-6

divide both sides by 3x

x=   -6