Can anyone solve this, and show the work for it? x² -6x - 16 = 0?

Question

Can anyone solve this, and show the work for it? x² -6x - 16 = 0?

Answer 1

It's a quadratic equation

1. You need to factorise

2. What number times to equal -16 but adds to equal -6?

3. The answer is -8 and 2

Therefore, your answer is

(x-8)(x+2)

Answer 2

x² -6x - 16 = 0

(x-8)(x+2)

That is your answer.

since when you expand it, it will equal x² -6x - 16 = 0

Answer 3

x^2 - 6x - 16 = 0

(x - 8)(x + 2) = 0

x - 8 = 0

x = 8

...OR...

x + 2 = 0

x = -2

Answer 4

You need to simplify:

(x+2)(x-8)=0

Then solve each x+2=0 -> x= -2  and x-8=0 -> x=8

Answer 5

factor it out

x² -6x - 16 = 0

(x+2)(x-8)

(x+2)=0 ==> x= -2

(x-8)=0  ==> x=8

Answer 6

x^2-6x-16=x^2-8x+2x-16=0

x(x-8)+2(x-8)=0

(x+2)(x-8)=0

x=-2 or x=8