Can basketball be translated in a quadratic function(math)? How?

Question

please make a situation and give a complete solution to the situation....

Answer 1

I think you mean the path of a thrown basketball follows a quadratic function s(t) where t is time.

Answer 2

y = high of ring

x = distance ball-ring in absis

A = angle of elevation

v = velocity of ball

t = time consumed

g = gravity

so :

x = v*t*cos(A)

y = v*t*sin(A) - 1/2*g*t^2

then:

y= f(x) = v^2 *tan(A) - 1/2*g*[x/v]^2 *sec^2(A)