Can "you" help me solve algebra equations?

Question

I'm in geometry but we are reviewing algebra and i totally forgot how to do it I need major help and the teacher wouldn't help. Just a couple questions then I can figure the rest out, Thank You.

2x/5-1=3... x=???

4j=5(7j-3)=9(j-5)... j=???

-16y--4... y=???

c/7+2=1... c=???

Answer 1

what is the .... ? I'll ignore it

2x/5-1=3

you need to use parans. Is this

(2x/5) - 1 = 3

or

2x/(5-1) = 3

case 1

(2x/5) - 1 = 3

2x/5 = 4

2x = 20

x = 10

case 2

2x/(5-1) = 3

2x/4 = 3

2x = 12

x = 6

4j=5(7j-3)=9(j-5)

two equals signs not allowed.

-16y--4

not an equation, can't be solved

c/7+2=1

again, two possibilities, too tired to do both.

.

Answer 2

you need to be more specific with your problems

1. is it 2x/(5-1)=3 or is it two-fifth times x minus 1 = 3?

2. Distribute your 5 and 9 to the two terms in the parantheses

3. What is it equal to?

4. same thing as 1. is it c/(7+2)=1 or (c/7)+2 = 1?

Answer 3

1) 2x/5-1=3 ... add one to both sides, 2x/5=4 ... mutliply both sides by 5, 2x=20. therefore x=10

2) ?? I never had a problem with two equals signs.  I have solved two equations, each that had one equal sign.  Which equation is equal to what?

3) The equation can be equal to anything - we need an equals sign and a value the expression is equal to.

4) c/7+2=1 ... subtract 2 to both sides, c/7=-1 ... divide both sides by 7, c=-1/7