Can someone help me answer this please?

Question

A reaction combines 64.81 grams of silver nitrate with 92.67 grams of potassium bromide. AgNO3 +KBr ---->AgBr +KNO3. How much of the excess reactant is left over? The excess reactant is KBr.

Answer 1

Greetings,

GFM AgNO3 = 169.87 g

GFM KBr = 119 g

mol AgNO3 = 64.81/169.87 = 0.3815 mol

mol KBr = 92.67/119 = 0.7787 mol

excess mol = 0.7787 - 0.3815 = 0.3972 mol

mass KBr left over = 119*0.3972 = 47.27 grams

Regards