Can someone help me with my homework??

Question

A steam catapult launches a jet aircraft from the aircraft carrier John C. Stennis, giving it a speed of 205 mi/h in 2.90 s.

(a) Find the average acceleration of the plane in m/s

b) Assuming that the acceleration is constant, find the distance the plane moves in m.

Answer 1

a)

1st velocity = 0

2nd velocity = 205 * ( 1609/3600 ) = 91.6 m/s

the average acceliration = the average velocity / time

                                   =( 91.6 - 0 ) / 2.90  = 31.6

b)

velocity = ditance / time

distance = time * velocity

             = 2.90 * 91.6   = 256.64 m

Answer 2

a) Initial velocity u = 0

Final velocity v = 205 mi/h = 205 * 1609/3600 m/s = 91.6 m/s

Time t = 2.90 s

Average acceleration a = (v-u)/t

= (91.6 - 0)/2.90 m/s^2

= 31.59 m/s^2

b) For constant acceleration,

average speed = (u + v)/2 = (0 + 91.6)/2 m/s

= 45.8 m/s

Distance = average speed * time = 45.8 * 2.90 m

= 132.82 m

Answer 3

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Answer 4

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