Can someone help me with this chemistry question please ?

Question

describe how you would prepare 20 mL of a 2 % solution of acrylamide from a 30 % stock solution.

thank you and I appreciate your helppppppppppppp

Answer 1

{20mL ( 2 % )}/30% = 20/15 = 1.333 mL of 30% diluted to 20 mL = 2%