Question:

Can someone help me with this math word problem please?

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According to the 1998 Guinness Book of World Records stuntman Dan Koko fell a distance of 332 feet into an airbag after jumping from the Vegas World Hotel and Casino. The distance d in feet traveled by a freefalling object in t seconds is given by the formula d = 16t 2. To the nearest tenth of a second, how long did the stuntman's freefall last?

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5 ANSWERS


  1. 4.6 seconds answer mine

    http://answers.yahoo.com/question/index?...


  2. d = 16t^2

    332 = 16t^2

    332/16 = t^2

    20.75 = t^2

    t = +- sqrt(20.75)

    t = +- 4.5552

    Since we're dealing with time, we can neglect the -ve root, and the answer to the nearest tenth of a second is 4.6s

  3. im assuming the 2 means squared here.

    just plug in the info you were given and boom.

    332 = 16t^2

    Divide 16 both sides.

    20.75 = t^2

    sqrt 20.75 = t

    t = 4.6 seconds

  4. d=16t^2

    when d = 332 feet

    332 = 16t^2

    332/16 = t^2

    20.75 = t^2

    t = SQRT 20.75

    t = 4.55521679 seconds

    therefor t = 4.55521679 rounded to nearest tenth of a second the fall lasted 4.6 seconds

  5. Simply plug 332 feet in for d.

    332=16t*2

    332=32t

    10.375=t

    10.4 seconds =t

    Edit: Was the two an exponent or were you multiplying 16t by 2?

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