Can someone please find the value of x to this following problems ? 3(x+5)=15+3x and -5x=5(4-x) ?

Question

Can someone please find the value of x to this following problems ? 3(x+5)=15+3x and -5x=5(4-x) ?

Answer 1

3(x+5)=15+3x

-5x=5(4-x)

15x+15=15+3x/-15

                      /-3x

-5x=20-5x/-5x

--------------------------------

12x=0/:0

x=R

-10x=20/:(-1)

12x=0:

10x=20/:2

x=2

i'm sorry if theres any mistakes its like 2:00 a.m here so im kinda sleeping on the keys here

Answer 2

3(x+5)=15+3x

x=0 cause there the same ****!

&

-5x=5(4-x)

-5x=20-5x

-5x+5x=20

x=20

Answer 3

3(x+5)=15+3x

All numbers.

3(x+5)=15+3x

No Solution.  

Answer 4

works like this

3(x+5)=15+3x

3x+15=15+3x

3x-3x=15-15

       x=0

and

      -5x=5(4-x)

      -5x=20-5x

-5x+5x=20

        x=20

Answer 5

first one x = 0 , second one x= null or invalid because 4 cannot be equal to 0

Answer 6

ok seriously this is easy

distribute the 3 in the the first problem..

so then its 3x+15

and both sides of the equation equal each other so x=1

and the second one you need to distribute the second half of the problem so...

-5x=20-5x

          +5x

x=20

Answer 7

There is no answer to either. "undefined" is what you could call it. Both equations have numbers and variables on each side that cancel completely, leaving no "x" to be used in the answer "x = whatever." By definition, an x is considered 1x. If it is completely canceled, then there is no way to answer the problem. Undefined.

Answer 8

as you see both sides of the = are the same in the first one so x can be ANY NUMBER so we just need to do the second one:

-5x=20-5x  

this one has no answer because you cant replace x by any no.

Answer 9

x=0 for the first one..

second one is probaby 0, but im not sure