Can someone please help me to obtain the range of values for "p" in this equation?

Question

2x^2- (3-p)x+p+3=0 using the b^2-4ac < 0

Answer 1

[3-p]^2-8[p+3] greater than or equal to zero

9+p^2-6p-8p-24 greater than or equal to zero

p^2 -14p -15=0greater than or equal to zero

[p-15][p+1] greater than or equal to zero

==&gt; the range of p is R-(-1,15)