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Can someone please help me with this algebra?

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8√32 - 4√8

and will you give step-by-step directions on how to solve it.

thanks.

:)

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  1. 8√32 - 4√8

    8*sqrt(32) - 4*sqrt(8)

    8*sqrt(16*2) - 4*sqrt(4*2)

    8* 4*sqrt(2) - 4 * 2*sqrt(2)

    32*sqrt(2) - 8*sqrt(2)

    24*sqrt(2)


  2. = 8√32 - 4√8 determine the square roots of the constants

    = 8(5.656854) - 4(2.828427) multiply the square roots with their coefficients

    = 45.25483 - 11.31371 simplify & ¡Bingo!

    = 33.94112

    Answer: 33.94112

    Another way:

    = (√2)([8√1/2{32}] - [4√1/2{8}])

    = (√2)([8√16] - [4√4])

    = (√2)([8{4}] - [4{2}])

    = (√2)(32 - 8)

    = (√2)(24)

    = 1.414214(24)

    = 33.94112



  3. Step 1. Simplify 8√32 to its lowest terms.

    8V32        

    to do this look at what is inside the radical and see if it has any perfect squares.

    32

    ^

    8x4

    16x2

    32x1

    since 16 is a number that has a perfect square, this is the best choice.

    Sixteen will turn into four times four, in which this case, when there are two numbers alike you take that number out only ONCE!  

          ^

         16 x 2=32    (sixteen times two=32)

          ^

        4x4  x 2 =32    (four x four x two = 32)

          ^

    the four is brought outside multiplied by the original 8 and the two is left in the radical since it cannot be simplified anymore.

    8*4 √2

    next multiply 8 and 4 and leave the 2 alone since it cant be simplified  =     32√2

    so now the equation looks like this....

    32√2- 4√8

    since we simplified the first radical completely we see that it is two, which means that once you simplify the other it will also have a radical 2.    (√2)

    now simplify 4√8 following the previous steps:

    4√8

    1x8

    2x4

    8x1

    we see that four is a perfect square... 2x2=4

    so now the equation looks like

    4√ 2 x 2 x 2

        cross out the pair of two's inside the radical and take it outside.

    4*2 √2          

    it'll leave only one two which is what we were looking for.

    multiply 4 and 2 and leave the radical..

    8√2

    now bring the simplified radicals together and it will be reallyyy simple.

    32√2 - 8√2

    the only thing left to do is subtract like terms.

    since the radical is the same you are finally allowed to subtract.

    Think of it as a fraction. 1/2 - 4/5   u would need to convert the fractions into like terms before subtracting them, so do the same with radicals.

    the answer is  24√2


  4. Find the largest perfect square that goes into 32.

    Perfect squares are 4, 9, 16, 25, 36, etc.

    32 = 16 * 2 and 16 is a perfect square

    Do the same for the 8

    8 = 4 * 2 and 4 is a perfect square

    so 8 * sqr(16) * sqr(2) - 4 * sqr(4) * sqr (2)

    8 * .......4.......* sqr(2) - 4 * 2 * sqr(2)

    (I'm using dots to keep things lined up)

    32 * sqr(2) - 8 * sqr(2)

    Since they both have sqr(2), they are LIKE TERMS so you can put the 32 - 8 together

    24* sqr(2) <=== Solution

    Good luck to you !


  5. 8 in to thirty two is (4) minus um.... idk i dont want to do your home work

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