Can someone please tell me how to do this question! thanks 121-9(x-1)^2?

Question

Can someone please tell me how to do this question! thanks 121-9(x-1)^2?

Answer 1

What do you want done ?

Factorise perhaps ?

121 - 9 (x² - 2x + 1)

121 - 9x² + 18x - 9

- 9x² + 18x + 112

(- 3x + 14)(3x + 8)

Answer 2

Use the identity a^2-b^2 = (a+b)(a-b)   You can multiply RHS to verify

121 - 9(x-1)^2

(11)^2 -   3^2(x-1)^2

[11]^2 - [3(x-1)]^2

Use identity at this step

(11+3x-3)(11-3x+3)

(8+3x)(14-3x)

If u hav to factorise this is the answer

If you hav 2 find out values of x equate this to zero

(8+3x)(14-3x) = 0

8+3x =0  or  14-3x = 0

x= (-8/3)  or x=14/3

Answer 3

121-9(x-1)^2

121-9(x^2-2x+1)

121-9x^2+18x-9

-9x^2+18x+112

Answer 4

121-9(x-1)^2

11^2-{3(x-1)}^2

11^2-{3(x-1)}^2

(11+3x-3)(11-3x+3)     ( a^2-b^2={a+b}{a-b} )

(8+3x)(14-3x)

Answer 5

(11+3(x-1))(11-3(x-1)

Answer 6

1) 121-9(x-1)^2

2) 121-9(x-1)(x-1)

3) 121- 9(x^2 -2x +1)

4) 121 - 9x^2 + 18x - 9

5) final answer: -9x^2 + 18x +112