Can someone pls help with this math??

Question

3x*2-x-4 factor completely 10 poionts !plssssssssssss

aslo thses ones too 6x*2-5x-25

8x*4+1

2x*2-3x-5

Answer 1

3x^2 - x - 4

= (3x - 4)(x + 1)

6x^2 - 5x - 25

= (3x + 5)(2x - 5)

8x^4 + 1

this... cannot help u...

2x^2 - 3x - 5

= (2x - 5)(x + 1)

Answer 2

Are you using x*2 to indicate exponentiation?

that is totally incorrect! * means multiply. Use ^

3x²-x-4

(3x - 4)(x + 1)

6x²-5x-25

(3x + 5)(2x - 5)

8x⁴ +1

y = x²

8y² + 1

quadratic equation:

to solve ax² + by + c = 0

x = [-b ±√(b²-4ac)] / 2a

y =  [ ±√(-4*8)] / 16

y = ±i√2/4

which means factors are

(x² + i√2/4)(x² - i√2/4)

2x²-3x-5

(2x - 5)(x + 1)

.