Question:

Can someone plz help me with this poisson/binomial problem?

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A glass make manufactures sheets of glass, the sheets have faults called seeds that occur randomly and independantly of each other at a rate of 1 per 10m^2.

Find the probability that in a set of 20 sheets each measuring 3.2m by 4m there are exactly 18 sheets with no more than 3 seeds.

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  1. ANSWER: BINOMIAL P(18) = 0.151  (15.1% PROBABILITY EXACTLY 18 SHEETS WITH NO MORE THAN 3 SEEDS)

    Why???

    BINOMIAL PROBABILITY = n! / [r! * (1 - p) ] * p^r * (1 - p)^(n - r)

    n = NUMBER OF TRIALS [20]

    r = NUMBER OF SUCCESSES [18]  (18 sheets with no more than 3 seeds)

    p = PROBABILITY OF SUCCESS [0.958874]

    Probability Density Function

    Binomial with n = 20 and p = 0.958874

    x  P( X = x )

    18    0.150902

    - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

    p = PROBABILITY OF SUCCESS - POISSON [rate of 1 per 10m^2]

    POISSON DISTRIBUTION, NUMBER OF TIMES AN "EVENT" OCCURS

    P(x) = [exp(-λ) * λ^x] / x!

    λ = AVERAGE VALUE PARAMETER PER SHEET

    λ = [1/(10m^2)] * (3.2 * 4) = 1.28 SEEDS/SHEET

    x = NUMBER OF EVENTS [x ≤ 3]

    Cumulative Distribution Function

    Poisson with mean = 1.28

    x  P( X <= x )

    3     0.958874

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