Can someone show me how to factor this general quadratic equation?

Question

The equation is: Ax^2 + Bx + ((B^2)/4)

I need to factor it, so that its in the form: (c + d)^2

but I'm not sure how to do that.

Answer 1

Ax^2 + Bx + ((B^2)/4)

find the factors using quad .formula

x= -B +- sqrt(B^2 -AB^2) / 2A

x= -B + - Bsqrt(1-A) / 2A

x= B[ -1+ - sqrt(1-A)] / 2A

so , the factors of above equation will be

={x- B[ -1+  sqrt(1-A)] / 2A} {x+B[ 1+ sqrt(1-A)] / 2A}

it cannot be a whole square.

Answer 2

(ax +b/2)^2

lets test it (ax +b/2)*(ax +b/2) = a^2 x^2 + abx/2 + abx/2 + b^2 /4

= a^2 x^2 + abx + b^2 /4



i think u typed it in wrong?????