Can someone solve this pls?

Question

Bea raised some cows and some turkey. She raised a total of 28 cows and turkeys. There were 96 legs in all. How many cows and how many turkeys did Bea raise?

the answers has to be solved in a algebraic equation

Answer 1

4c+2t=96

c+t=28

c=28-t

4(28-t)+2t=96

112-4t+2t=96

112-2t=96

16-2t=0

2t=16

t=8

c=20

Answer 2

Let,  x cows, y turkeys

x+y=28

4x+2y=96;

4x+2(28-x)=96

x=20

y=8