Can somone please help me?

Question

Question 1

Find - 4x^2y(3xy^2 - 2x^4 - y)

a - x3y^3 - 6x^6y - 4x^2y^2

b - 12x^3y^3 + 8x^6y + 4x^2y^2

c - 12 x^2y^2 + 6x^8y + 4x^2y

d - 7x^3y^3 - 6x^6y - 4x^2y^2

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Question 2

Write an expression for the area of the rectangle with length 2x^2y + 3xy^2 and width x^2y^2.

a. 2x^4y^3 + 3x^3y^4

b. 3x^4y^3 + 4x^3y^4

c .5x^3y^3

d .2x4y^2 + 3x^2y^4

Answer 1

Let's break this down a bit so you can figure out this things on your own.

Question one:

Let's make it a little easier. Do you know what -4(3x^2y) would be? How about -4(3)? You have to multiply what's on the outside to what's on the inside, term by term. So, start with -4x^2y(3xy^2): you have -4 times 3, and x^2 times x, and y times y^2. Right there, you can already select the correct answer. To actually solve the whole thing, you'd move to your next term: -4x^2y(-2x^4). Then to your third term: -4x^2y(y).

For question 2, what is the area of a rectangle? length times width. So, they are asking you to solve

(2x^2y + 3xy^2)(x^2y^2).

Answer 2

Question 1:

b)

Question 2:

a)

Answer 3

I agree with Glurpy

Just make sure you ask your teacher for some more of these math questions and do them at home for extra support in them.