Can you HELP me solve this equation for y?

Question

if 3x+4y=14

and (2x)^2(x^2)^3 y = -5/2x

y=?

If you can not assist , please no response.

Answer 1

Here goes:

We take the two equations 1 and 2

Get each equation in its simplest form and then...

Get 1 equation in terms of x and other in terms of y. Equate both of them and you will get the reqired values of x and y !!

Hope it helps!

Answer 2

well if u r looking for an even number for x i gota disappoint u

I x = -4y/3 +14/3  plug this into II

II y = -5/(x^7)

  

Answer 3

(2x)^2(x^2)^3 y = -5/2x

simplifying

4x^2 *x^6 *y = -5x/2

4x^6 * y =  -5x/2

so y  = -5x/8 x^6

= -5x^-5/8

y = -5/ 8x^5

but we also know from the first equation that x = (14-4y)/3



u want things in terms of y  or y =?

basically u are trying to find where these 2 things intersect.

y = -5/ 8[(14-4y)/3]^5